$\int {\cfrac{{2 - 3\sin x}}{{{{\cos }^2}x}}dx}$
$\int {\cfrac{{2 - 3\sin x}}{{{{\cos }^2}x}}dx}$
Official Solution
VVidaara Team
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NCERT & Exemplar
: Let$I = \int {\cfrac{{2 - 3\sin x}}{{{{\cos }^2}x}}dx} = \int {\left( {\cfrac{2}{{{{\cos }^2}x}} - 3\cfrac{{\sin x}}{{{{\cos }^2}x}}} \right)dx}$
$= \int {\left( {2{{\sec }^2}x - 3\sec x\tan x} \right)dx} = 2\tan x - 3\sec x + C$
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