$\int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx}$
$\int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx}$
Official Solution
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NCERT & Exemplar
: Let$I = \int {{x^2}\left( {1 - \cfrac{1}{{{x^2}}}} \right)dx} = \int {\left( {{x^2} - 1} \right)dx} = \cfrac{{{x^3}}}{3} - x + C$
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