$\sqrt {ax + b}$
$\sqrt {ax + b}$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
.: Let$I = \int {\sqrt {ax + b} d} x = \int {{{\left( {ax + b} \right)}^{1/2}}dx}$
$= \cfrac{{{{\left( {ax + b} \right)}^{3/2}}}}{{\cfrac{3}{2}a}} + C = \cfrac{2}{{3a}}{\left( {ax + b} \right)^{3/2}} + C$
Community Answers (0)
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.