$\cfrac{{{{\sin }^2}x}}{{1 + \cos x}}$
$\cfrac{{{{\sin }^2}x}}{{1 + \cos x}}$
Official Solution
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NCERT & Exemplar
: Let $I = \int {\cfrac{{{{\sin }^2}x}}{{1 + \cos x}}} dx = \int {\cfrac{{1 - {{\cos }^2}x}}{{1 + \cos x}}} dx$
$= \int {\left( {1 - \cos x} \right)dx} = x - \sin x + C$
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