The domain of the function defined by $f(x) = {\sin ^{ - 1}}\sqrt {x - 1}$ is
The domain of the function defined by $f(x) = {\sin ^{ - 1}}\sqrt {x - 1}$ is
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$\Rightarrow$ $0 \le x - 1 \le 1$
and $- 1 \le \sqrt {x - 1} \le 1]$
$\Rightarrow$ $1 \le x \le 2$
$therefore, x \in [1,2]$
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