Work problems are about rates: if a worker finishes a job in x hours, the rate is 1/x of the job per hour. To combine workers, add their rates: together they do 1/x + 1/y per hour, so the whole job takes (x·y)/(x + y) hours. For staffing questions, the number of worker-days (or worker-hours) is constant: M workers × D days = the same total, so N workers take (M·D)/N days — more workers, fewer days (inverse proportion). Identify whether rates add (working together) or scale inversely (more workers), set up the constant, and solve.
✅ Solved examples
1. A does a job in 6 h, B in 12 h. Together?
(6·12)/(6 + 12) = 72/18 = 4 hours.
2. 4 workers build a wall in 6 days. How long for 8 workers?
Worker-days = 24; 24/8 = 3 days.
3. A in 10 h, B in 15 h. Together?
(10·15)/25 = 150/25 = 6 hours.
4. 5 machines fill an order in 8 hours. How long for 10 machines?
5·8 = 40 machine-hours; 40/10 = 4 hours.
✏️ Practice — try these, take hints as needed
1. A does a job in 4 h, B in 12 h. Together?
(xy)/(x + y).
(4·12)/16.
48/16.
3 hours.
2. 6 workers finish in 10 days. How long for 12 workers?
Worker-days constant = 60.
60/12.
—
5 days.
3. A in 20 h, B in 30 h. Together?
(20·30)/50.
600/50.
—
12 hours.
4. 3 painters take 8 hours. How long for 4 painters?
24 painter-hours.
24/4.
—
6 hours.
5. A in 8 h, B in 8 h. Together?
(8·8)/16.
—
—
4 hours.
📝 Topic test — 8 questions
Auto-graded with full solutions; saved to your dashboard. Use the calculator and formula sheet (top-right) any time.
Vidaara uses essential cookies to run the site and, with your consent, optional cookies to understand how learners use Vidaara so we can improve it. We never sell your data. Read our Cookie Policy and Privacy Policy.