$\left| {\begin{array}{cccccccccccccccccccc}{a + x}&y&z\\x&{a + y}&z\\x&y&{a + z}\end{array}} \right|$
Determinants — Class 12 Maths Solution
Question
Step-by-step Solution
We have, $\left| {\begin{array}{cccccccccccccccccccc}{a + x}&y&z\\x&{a + y}&z\\x&y&{a + z}\end{array}} \right| = \left| {\begin{array}{cccccccccccccccccccc}a&{ - a}&0\\0&a&{ - a}\\x&y&{a + z}\end{array}} \right|$
$= \left| {\begin{array}{cccccccccccccccccccc}a&0&0\\0&a&{ - a}\\x&{x + y}&{a + z}\end{array}} \right|$
$= a\left( {{a^2} + az + ax + ay} \right)$
$= {a^2}(a + z + x + y)$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Determinants. Curated by Sachin Sharma. Free for all students.