Matrices • Topic 3 of 3

Addition and Subtraction of Matrices, and Multiplication by a Scalar

What is matrix addition and subtraction? When two matrices have the same order, we can add or subtract them by adding or subtracting the corresponding elements (elements in the same position).

Addition: If A = [aᵢⱼ] and B = [bᵢⱼ] are both m × n matrices, then: A + B = [aᵢⱼ + bᵢⱼ]

Subtraction: A − B = [aᵢⱼ − bᵢⱼ]

What is scalar multiplication? Scalar multiplication means multiplying every element of a matrix by the same number (called a scalar). If k is a scalar and A = [aᵢⱼ], then: kA = [k × aᵢⱼ]

Properties of scalar multiplication:

  • k(A + B) = kA + kB (distributive)
  • (k + m)A = kA + mA (distributive)
  • k(mA) = (km)A (associative)
  • 1 × A = A (identity)
  • 0 × A = Zero matrix

Real-life analogy: If matrix A represents the prices of items in two stores, and matrix B represents a price increase, then A + B gives the new prices. Scalar multiplication is like applying a 10% discount (multiply by 0.9) to all prices at once!

┌─────────────────────────────────────────────────────────────┐
│      ADDITION, SUBTRACTION, AND SCALAR MULTIPLICATION        │
└─────────────────────────────────────────────────────────────┘

MATRIX ADDITION (Element by element):

    A = [2  4]    B = [1  3]    A + B = [2+1  4+3] = [3  7]
        [5  7]        [2  6]            [5+2  7+6]   [7  13]
    
    ┌─────┬─────┐   ┌─────┬─────┐   ┌─────┬─────┐
    │ 2   │ 4   │   │ 1   │ 3   │   │ 3   │ 7   │
    ├─────┼─────┤ + ├─────┼─────┤ = ├─────┼─────┤
    │ 5   │ 7   │   │ 2   │ 6   │   │ 7   │ 13  │
    └─────┴─────┘   └─────┴─────┘   └─────┴─────┘


MATRIX SUBTRACTION:

    A = [7  5]    B = [3  2]    A - B = [7-3  5-2] = [4  3]
        [6  8]        [1  4]            [6-1  8-4]   [5  4]


SCALAR MULTIPLICATION:

    A = [1  2]    3A = [3×1  3×2] = [3  6]
        [3  4]          [3×3  3×4]   [9  12]
    
    Every element gets multiplied by the scalar!


COMBINED OPERATIONS (BODMAS rules apply):

    Given A = [1  2], B = [2  3], find 2A + 3B
              [3  4]     [4  5]
    
    Step 1: 2A = [2  4]
                [6  8]
    
    Step 2: 3B = [6  9]
                [12 15]
    
    Step 3: 2A + 3B = [2+6  4+9] = [8  13]
                     [6+12 8+15]   [18 23]


RULES AT A GLANCE:

┌─────────────────────────────────────────────────────────┐
│  Operation        │  Condition        │  How to Compute  │
├───────────────────┼───────────────────┼──────────────────┤
│  A + B            │  Same order       │  Add elements    │
│  A - B            │  Same order       │  Subtract elements│
│  kA               │  Any matrix       │  Multiply each   │
│                   │                   │  element by k    │
└───────────────────┴───────────────────┴──────────────────┘
1
Worked Example
If A = [1 2; 3 4] and B = [5 6; 7 8], find A + B and A − B.
Solution
  1. Step 1: A + B = [1+5, 2+6; 3+7, 4+8] = [6, 8; 10, 12]
  2. Step 2: A − B = [1−5, 2−6; 3−7, 4−8] = [−4, −4; −4, −4]

Answer: A + B = [6 8; 10 12]; A − B = [−4 −4; −4 −4]

2
Worked Example
Given A = [2 4; 6 8], find 5A.
Solution
  1. Step 1: Multiply each element by 5: 5×2 = 10, 5×4 = 20, 5×6 = 30, 5×8 = 40

Answer: 5A = [10 20; 30 40]

3
Worked Example
If A = [3 1; 2 4] and B = [2 3; 1 5], find 3A − 2B.
Solution
  1. Step 1: 3A = [9 3; 6 12]
  2. Step 2: 2B = [4 6; 2 10]
  3. Step 3: 3A − 2B = [9−4, 3−6; 6−2, 12−10] = [5, −3; 4, 2]

Answer: 3A − 2B = [5 −3; 4 2]

Key Points

  • Addition/subtraction only possible for matrices of same order
  • Add/subtract corresponding elements (same row, same column)
  • Scalar multiplication multiplies EVERY element by the scalar
  • Scalar multiplication is distributive over addition
  • Zero matrix (all zeros) is the additive identity
  • Order remains the same after addition, subtraction, and scalar multiplication
Tap an option to check your answer0 / 4
Q1.Matrices are added:
Explanation: Add corresponding entries.
Q2.Scalar multiplication multiplies:
Explanation: Each entry by the scalar.
Q3.$2\begin{bmatrix}1&2\\3&4\end{bmatrix}=$
Explanation: Double each entry.
Q4.$A-A=$
Explanation: All entries become $0$.