Arithmetic Progressions • Topic 1 of 5

Introduction to Arithmetic Progression (AP

What is a Sequence? A sequence is an ordered list of numbers arranged according to a definite rule. The numbers in a sequence are called its terms, and we name them $t_1, t_2, t_3, \dots$ (or $a_1, a_2, a_3, \dots$) according to their position. For example, in $2, 4, 6, 8, 10, \dots$ each term is $2$ more than the one before it.

What is a Series? A series is what you get when the terms of a sequence are added: $2 + 4 + 6 + 8 + 10 + \dots$ A sequence simply lists the numbers; a series totals them. This chapter is built around one very common and useful kind of sequence.

What is an Arithmetic Progression (AP)? An Arithmetic Progression is a sequence in which each term, except the first, is obtained by adding a fixed number to the previous term. That fixed number is called the common difference, written $d$. Because the same amount is added every time, the terms move in equal steps.

The defining condition. For a list $t_1, t_2, t_3, t_4, \dots$ to be an AP, the difference between each term and the one before it must be the same: $t_2 - t_1 = t_3 - t_2 = t_4 - t_3 = \dots = d$. Notice the subtraction is always later term minus earlier term ($t_{k+1} - t_k$), never the other way round. Getting this order wrong is the single most common mistake, because it flips the sign of $d$.

How to test a list for AP. Take consecutive differences across the whole list. If every difference comes out equal, it is an AP and that common value is $d$. If even one difference disagrees, the list is not an AP. Checking just the first two terms is not enough — a list like $2, 4, 6, 10$ passes the first check but fails at $10 - 6 = 4 \ne 2$, sorry, $6-4=2$ but $4-2=2$ and $10-6=4$, so it is not an AP.

The three flavours of AP. If $d > 0$ the terms grow — an increasing AP (e.g. $3, 7, 11, 15$). If $d < 0$ the terms shrink — a decreasing AP (e.g. $20, 17, 14, 11$). If $d = 0$ every term is identical (e.g. $5, 5, 5, 5$); this is a constant AP, and yes it still counts as an AP.

Finite and infinite APs. An AP with a definite number of terms ($3, 6, 9, 12, 15$) is finite and has a last term. An AP that continues without end ($3, 6, 9, \dots$) is infinite and has no last term. The three dots "$\dots$" signal that the pattern carries on.

Why APs matter. Equal-step patterns appear everywhere: a salary that rises by a fixed raise each year, the seats in successive rows of a hall, the rungs of a ladder, the money saved each month under a fixed-increment plan, even the cost of a taxi where each kilometre adds a flat charge. Recognising an AP lets you jump straight to any term or total without listing everything.

  • A monthly salary that increases by a fixed amount every year.
  • Seats per row in an auditorium that grow by a constant from front to back.
  • The water level in a tank falling by a fixed amount each hour.
  • The amount repaid each year on a loan settled in equal-step instalments.

Common mistakes to avoid. (1) Subtracting in the wrong direction and reporting $+d$ as $-d$. (2) Declaring a list an AP after checking only one gap. (3) Assuming a "nice looking" list such as $1, 4, 9, 16$ (squares) or $2, 4, 8, 16$ (doubling) is an AP — neither is, because their differences are not constant. Always verify with actual subtraction.

Number line showing the AP 3, 7, 11, 15, 19 with equal +4 steps between termsAn AP moves in equal steps (common difference d)37111519+4+4+4+4Every gap is the same, so d = 4 (an increasing AP)Two panels: a sequence is a list, a series is the sum; plus increasing versus decreasing AP examplesSequence vs Series; Increasing vs DecreasingSequence (a list)3, 7, 11, 15, 19, …terms in orderSeries (a sum)3 + 7 + 11 + 15 + …terms added togetherIncreasing AP (d > 0)2, 5, 8, 11, 14d = +3, terms growDecreasing AP (d < 0)30, 25, 20, 15, 10d = −5, terms shrink
1
Worked Example
Check whether the sequence 7, 11, 15, 19, 23 is an arithmetic progression. If yes, find the common difference.
Solution
  1. Subtract each term from the one after it.
  2. $11 - 7 = 4$
  3. $15 - 11 = 4$
  4. $19 - 15 = 4$
  5. $23 - 19 = 4$
  6. All four differences are equal, so the list is an AP with $d = 4$.

Answer: Yes, it is an AP with common difference $d = 4$.

2
Worked Example
The first four terms of a sequence are 2, 6, 10, 14. Is it an AP? If yes, write the next three terms.
Solution
  1. Differences: $6 - 2 = 4$, $10 - 6 = 4$, $14 - 10 = 4$.
  2. All equal, so it is an AP with $d = 4$.
  3. Next term: $14 + 4 = 18$.
  4. Then: $18 + 4 = 22$.
  5. Then: $22 + 4 = 26$.

Answer: Yes, AP with $d = 4$; next three terms are 18, 22, 26.

3
Worked Example
Is the sequence 1, 4, 9, 16, 25 an arithmetic progression? Justify your answer.
Solution
  1. Differences: $4 - 1 = 3$, $9 - 4 = 5$, $16 - 9 = 7$, $25 - 16 = 9$.
  2. The differences $3, 5, 7, 9$ are not equal.
  3. Since the gaps keep changing, the constant-difference condition fails.

Answer: No, it is not an AP (these are perfect squares, whose differences increase).

4
Worked Example
For the AP 21, 18, 15, 12, ... find the common difference and state whether it is increasing or decreasing.
Solution
  1. $d = 18 - 21 = -3$ (check: $15 - 18 = -3$, $12 - 15 = -3$).
  2. The common difference is $-3$.
  3. Since $d < 0$, the terms get smaller as we move along.

Answer: $d = -3$; it is a decreasing AP.

5
Worked Example
Write the first four terms of the AP whose first term is $a = -2$ and common difference is $d = 5$.
Solution
  1. First term $= a = -2$.
  2. Second term $= -2 + 5 = 3$.
  3. Third term $= 3 + 5 = 8$.
  4. Fourth term $= 8 + 5 = 13$.

Answer: $-2,\ 3,\ 8,\ 13$.

6
Worked Example
For each list, write the first term $a$ and the common difference $d$: (i) 0.6, 1.7, 2.8, 3.9 (ii) $-1.2, -3.2, -5.2, -7.2$.
Solution
  1. (i) $a = 0.6$; $d = 1.7 - 0.6 = 1.1$ (each later gap is also $1.1$).
  2. (i) So $a = 0.6,\ d = 1.1$.
  3. (ii) $a = -1.2$; $d = -3.2 - (-1.2) = -2$.
  4. (ii) So $a = -1.2,\ d = -2$.

Answer: (i) $a = 0.6,\ d = 1.1$; (ii) $a = -1.2,\ d = -2$.

7
Worked Example
A farmer saves ₹500 in the first month, ₹700 in the second month and ₹900 in the third month, continuing the same pattern. Show that the savings form an AP and find the savings in the 6th month.
Solution
  1. Savings: 500, 700, 900, ...
  2. Differences: $700 - 500 = 200$, $900 - 700 = 200$, so $d = 200$ — it is an AP.
  3. 4th month: $900 + 200 = 1100$.
  4. 5th month: $1100 + 200 = 1300$.
  5. 6th month: $1300 + 200 = 1500$.

Answer: Yes, AP with $d = 200$; savings in the 6th month $=$ ₹1500.

8
Worked Example
The taxi fare is ₹15 for the first kilometre and ₹8 for each additional kilometre. Write the AP for the total fare after 1, 2, 3 and 4 km.
Solution
  1. After 1 km: ₹15.
  2. After 2 km: $15 + 8 = $ ₹23.
  3. After 3 km: $23 + 8 = $ ₹31.
  4. After 4 km: $31 + 8 = $ ₹39.
  5. The fares 15, 23, 31, 39 differ by a constant $8$, so they form an AP.

Answer: Fares: 15, 23, 31, 39 (an AP with $a = 15,\ d = 8$).

9
Worked Example
For what value of $x$ are the numbers $2x,\ x + 10,\ 3x + 2$ in AP?
Solution
  1. In an AP, the middle term minus the first equals the third minus the middle.
  2. So $(x + 10) - 2x = (3x + 2) - (x + 10)$.
  3. Left side: $10 - x$. Right side: $2x - 8$.
  4. $10 - x = 2x - 8 \Rightarrow 18 = 3x \Rightarrow x = 6$.

Answer: $x = 6$.

10
Worked Example
The terms $3k + 2,\ 5k - 2,\ 7k + 4$ are in AP. Find $k$ and write the three terms.
Solution
  1. Equal gaps: $(5k - 2) - (3k + 2) = (7k + 4) - (5k - 2)$.
  2. Left: $2k - 4$. Right: $2k + 6$.
  3. $2k - 4 = 2k + 6 \Rightarrow -4 = 6$, which is impossible.
  4. Re-check using $2 \times$ middle $=$ first $+$ third: $2(5k - 2) = (3k + 2) + (7k + 4)$.
  5. $10k - 4 = 10k + 6 \Rightarrow -4 = 6$ — still impossible, so no value of $k$ works.

Answer: No value of $k$ makes these three terms an AP.

11
Worked Example
A list of numbers has $n$th term given by $a_n = 4n + 1$. Is this list an AP? Find the first three terms and the common difference.
Solution
  1. Put $n = 1, 2, 3$: $a_1 = 4(1)+1 = 5$, $a_2 = 4(2)+1 = 9$, $a_3 = 4(3)+1 = 13$.
  2. Differences: $9 - 5 = 4$ and $13 - 9 = 4$.
  3. Since the gap is the constant $4$, the list is an AP.
  4. In general $a_{n+1} - a_n = [4(n+1)+1] - [4n+1] = 4$, confirming $d = 4$.

Answer: Yes, it is an AP with first three terms $5, 9, 13$ and $d = 4$.

12
Worked Example
The water level in a tank is 80 cm and falls by 6 cm every hour. Write the levels after 0, 1, 2, 3 hours and state the common difference. Is it an increasing or decreasing AP?
Solution
  1. At 0 h: 80 cm.
  2. After 1 h: $80 - 6 = 74$ cm.
  3. After 2 h: $74 - 6 = 68$ cm.
  4. After 3 h: $68 - 6 = 62$ cm.
  5. The levels 80, 74, 68, 62 fall by a constant $6$, so $d = -6$.

Answer: Levels 80, 74, 68, 62 cm form a decreasing AP with $d = -6$.

Key Points

  • A sequence is an ordered list of numbers; a series is their sum.
  • An Arithmetic Progression (AP) has a constant difference between consecutive terms.
  • The common difference $d = t_{k+1} - t_k$ — always later term minus earlier term.
  • The common difference (d) can be positive (increasing AP), negative (decreasing AP), or zero (constant AP).
  • To identify an AP, check that every consecutive difference is equal — one check is not enough.
  • Squares ($1,4,9,16$) and doubling lists ($2,4,8,16$) are not APs — their differences change.
  • Real-life examples include fixed monthly savings, seating rows, taxi fares and falling water levels.
Tap an option to check your answer0 / 4
Q1.In an AP, consecutive terms differ by a constant called the:
Explanation: That constant is the common difference $d$.
Q2.$3,6,9,12,\dots$ is an AP with common difference:
Explanation: $6-3=3$.
Q3.Which of these is an AP?
Explanation: Constant difference $3$.
Q4.The common difference of $10,7,4,1$ is:
Explanation: $7-10=-3$.