Mensuration • Topic 1 of 3

Surface Area and Volume of Combination of Solids

What is a combination of solids? A combination of solids is a complex three-dimensional object formed by joining two or more basic three-dimensional shapes together. In the real world, very few things are pure shapes like an isolated cylinder or a perfect sphere. For instance, an ice cream cone is a combination of a cone topped by a hemisphere. A medical capsule is a cylinder with hemispheres stuck to both ends. A circus tent often looks like a cylinder capped by a cone.

When analyzing these real-world objects, we need to find their total surface area and total volume by looking at the individual shapes that make them up.

Total Surface Area (TSA) of Combined Solids When two shapes are joined together tightly, some of their individual faces get trapped inside and disappear from view. Therefore, the total surface area of a combined solid is the sum of only the visible outer surfaces.

  • Rule: Look only at what you can touch or paint from the outside.
  • Example: For a toy made by joining a cone to the flat base of a hemisphere, the joining surfaces are hidden inside. The total surface area is equal to the Curved Surface Area (CSA) of the cone plus the Curved Surface Area (CSA) of the hemisphere.

Total Volume of Combined Solids Volume measures the space trapped inside an object. Space does not disappear when objects are joined together.

  • Rule: The total volume is simply the sum of the volumes of all the individual shapes.
  • Example: The volume of our ice cream cone toy is the volume of the cone plus the volume of the hemisphere.
Shape ComponentCurved Surface Area (CSA)Total Surface Area (TSA)Volume
Cube (side $a$)$4a^2$$6a^2$$a^3$
Cuboid ($l, w, h$)$2h(l + w)$$2(lw + wh + hl)$$l \cdot w \cdot h$
Cylinder ($r, h$)$2\pi rh$$2\pi r(r + h)$$\pi r^2h$
Cone ($r, h, slant\ l$)$\pi rl$$\pi r(r + l)$$(1/3)\pi r^2h$
Sphere ($r$)$4\pi r^2$$4\pi r^2$$(4/3)\pi r^3$
Hemisphere ($r$)$2\pi r^2$$3\pi r^2$$(2/3)\pi r^3$

---

DIAGRAM 1: ICE CREAM CONE SOLID COMBINATION

                . - ~ ~ ~ - .
            .     Hemisphere  .
          /       Top Cap       \
         /                       \
        ;------------O------------;  <-- Joint face hidden inside
         \           |           /
          \          |          /
           \         |h        /
            \        |        /  Cone Component
             \       |       /
              \      |      /
               \     |     /
                \    |    /
                 \   |   /
                  \  |  /
                   \ | /
                    \|/
                  Vertex V

DIAGRAM 2: CAPSULE COMBINATION (CYLINDER + 2 HEMISPHERES)

        .-~~-.  _______________________  .-~~-.
       /      |                       |      \
      ;  Hemi |       Cylinder        | Hemi  ;
       \      |                       |      /
        '-__-'  -----------------------  '-__-'
        <- r -> <---------- h ---------> <- r ->
1
Worked Example
A solid toy is in the form of a hemisphere surmounted by a right circular cone. The radius of both the hemisphere and the cone is 3 cm, and the height of the cone is 4 cm. Find the total volume of the toy. (Take $\pi = 22/7$).
Solution
  1. Step 1: Identify the components and their dimensions.
  2. Hemisphere: Radius ($r$) = 3 cm.
  3. Cone: Radius ($r$) = 3 cm, Height ($h$) = 4 cm.
  4. Step 2: Apply the total volume rule.
  5. Total Volume = Volume of Hemisphere + Volume of Cone
  6. Step 3: Substitute formulas and insert the numbers.
  7. Volume of Hemisphere = $(2/3) \cdot \pi \cdot r^3 = (2/3) \cdot (22/7) \cdot 3 \cdot 3 \cdot 3 = (22/7) \cdot 18 = 396/7$ cubic cm.
  8. Volume of Cone = $(1/3) \cdot \pi \cdot r^2 \cdot h = (1/3) \cdot (22/7) \cdot 3 \cdot 3 \cdot 4 = (22/7) \cdot 12 = 264/7$ cubic cm.
  9. Step 4: Combine the component volumes.
  10. Total Volume = $396/7 + 264/7 = 660/7 = 94.28$ cubic cm.
  11. Answer: The total volume of the toy is 660/7 cubic cm (or approximately 94.28 cubic cm).
2
Worked Example
A solid test tube consists of a hollow plastic cylinder with a hemispherical bottom face. If the common radius of the cylinder and hemisphere is 7 cm, and the total length of the entire test tube is 27 cm, calculate the total outer surface area that can be painted. (Take $\pi = 22/7$).
Solution
  1. Step 1: Calculate the specific height of the cylindrical part.
  2. The total length includes the cylinder height ($h$) and the hemisphere radius ($r$).
  3. Total length = $h + r \implies 27 = h + 7 \implies h = 20$ cm.
  4. Step 2: Determine which surface areas are visible on the outside.
  5. Visible Outer Area = Curved Surface Area of Cylinder + Curved Surface Area of Hemisphere.
  6. Step 3: Apply formulas and compute values.
  7. CSA of Cylinder = $2 \cdot \pi \cdot r \cdot h = 2 \cdot (22/7) \cdot 7 \cdot 20 = 2 \cdot 22 \cdot 20 = 880$ sq. cm.
  8. CSA of Hemisphere = $2 \cdot \pi \cdot r^2 = 2 \cdot (22/7) \cdot 7 \cdot 7 = 2 \cdot 22 \cdot 7 = 308$ sq. cm.
  9. Step 4: Add the two areas together.
  10. Total Paintable Area = $880 + 308 = 1188$ sq. cm.
  11. Answer: The total outer surface area is 1188 sq. cm.
3
Worked Example
A wooden decorative block is made of a cube of side 5 cm with a hemisphere attached to the top face. The hemisphere has a diameter of 4.2 cm. Find the total surface area of the combined decorative block. (Take $\pi = 22/7$).
Solution
  1. Step 1: Analyze the surface modifications on the cube's top face.
  2. The hemisphere is placed on top, so it covers up a circular base area ($\pi r^2$) on the cube's top face.
  3. However, it adds its own curved surface area ($2\pi r^2$) into view.
  4. Total Area = Total Surface Area of Cube - Base Area of Hemisphere + Curved Surface Area of Hemisphere.
  5. Total Area = $6a^2 - \pi r^2 + 2\pi r^2 = 6a^2 + \pi r^2$.
  6. Step 2: Identify structural measurements.
  7. Cube side ($a$) = 5 cm.
  8. Hemisphere radius ($r$) = $4.2 / 2 = 2.1$ cm.
  9. Step 3: Execute individual calculations.
  10. Area of Cube base structure = $6 \cdot 5^2 = 6 \cdot 25 = 150$ sq. cm.
  11. Net added hemisphere area = $\pi r^2 = (22/7) \cdot 2.1 \cdot 2.1 = 22 \cdot 0.3 \cdot 2.1 = 13.86$ sq. cm.
  12. Step 4: Sum the components.
  13. Total Surface Area = $150 + 13.86 = 163.86$ sq. cm.
  14. Answer: The total surface area of the block is 163.86 sq. cm.
  15. --

Key Points

  • A combined solid is made by joining basic shapes like cylinders, cones, and spheres together.
  • The total volume of a combined solid is the sum of the volumes of its parts.
  • The total surface area includes only the outer, visible surfaces. Any face caught inside the joint must be subtracted.
  • When finding a cone's surface area, always calculate its slant height first using the formula $l = \sqrt{r^2 + h^2}$.
  • Carefully read problem dimensions to distinguish between the radius and the full diameter of an object.
Tap an option to check your answer0 / 4
Q1.The volume of a cylinder is:
Explanation: $\pi r^2h$.
Q2.The volume of a cone is:
Explanation: One-third of the cylinder.
Q3.The volume of a sphere is:
Explanation: $\tfrac43\pi r^3$.
Q4.The curved surface area of a cylinder is:
Explanation: $2\pi rh$.