How to Represent \(\sqrt{2}\) on a Number Line: We can use the Pythagorean theorem to construct irrational numbers geometrically.
Method for \(\sqrt{2}\):
- Draw a number line. Mark 0 and 1.
- At point 1, draw a perpendicular line of length 1 unit.
- Join 0 to the top of this perpendicular. The length of this line = \(\sqrt{1^2 + 1^2} = \sqrt{2}\).
- Using a compass, transfer this length to the number line.
Method for \(\sqrt{3}\):
- First construct \(\sqrt{2}\) as above.
- At point \(\sqrt{2}\), draw a perpendicular of length 1.
- Join 0 to the top. Length = \(\sqrt{(\sqrt{2})^2 + 1^2} = \sqrt{2 + 1} = \sqrt{3}\).
Approximation Methods for Irrational Numbers:
| Method | Description | Example for \(\sqrt{2}\) |
|---|---|---|
| Guess and check | Find perfect squares around the number | \(1^2=1\), \(2^2=4\), so \(\sqrt{2}\) is between 1 and 2 |
| Long division method | Systematic digit-by-digit calculation | 1.414213... |
| Using calculator | Quick approximation | 1.414213562 |
Approximating \(\pi\):
- \(\pi \approx 3.14\) (to 2 decimal places)
- \(\pi \approx 3.142\) (to 3 decimal places)
- \(\pi \approx \frac{22}{7} \approx 3.142857\) (fraction approximation)
- \(\pi \approx 3.1416\) (to 4 decimal places)