Irrational Numbers • Topic 2 of 3

Surds — Simplification & Operations

What is the Decimal Expansion of an Irrational Number? The decimal expansion of an irrational number is non-terminating (never ends) and non-repeating (no pattern repeats). You can keep calculating digits forever, and they will never settle into a repeating cycle.

Examples:

  • \(\sqrt{2} = 1.4142135623730950488...\) (never ends, no repeating pattern)
  • \(\pi = 3.14159265358979323846...\) (never ends, no repeating pattern)
  • \(\sqrt{3} = 1.7320508075688772935...\)

Contrast with Rational Numbers:

  • Terminating decimals: \(\frac{1}{4} = 0.25\) (ends)
  • Repeating decimals: \(\frac{1}{3} = 0.333333...\) (repeats 3)
  • Irrational: \(1.414213...\) (never ends and never repeats)

How do we know an irrational number's decimal never repeats? If a decimal expansion eventually repeats, the number can be written as a fraction (rational number). Since irrational numbers cannot be written as fractions, their decimal expansions cannot repeat.

Approximating Irrational Numbers: We often use approximations (rounded values) for irrational numbers in calculations:

  • \(\pi \approx 3.14\) or \(3.1416\)
  • \(\sqrt{2} \approx 1.414\)
  • \(\sqrt{3} \approx 1.732\)
Surds — Simplification Rules√(a×b) = √a × √be.g. √12 = √4×3 = 2√3√(a/b) = √a / √be.g. √(9/16) = 3/4(√a)² = ae.g. (√5)² = 5√a + √a = 2√ae.g. 3√2 + 5√2 = 8√2Rationalise: a/√be.g. = a√b/b√a × √b = √(ab)e.g. √3 × √7 = √21
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Worked Example
Classify the following decimals as terminating, repeating, or non-terminating non-repeating (irrational): (a) 0.375 (b) 0.272727... (c) 1.01001000100001...
Solution- (a) 0.375 ends after 3 digits → **Terminating decimal (Rational) - (b) 0.272727... repeats "27" → **Repeating decimal (Rational) - (c) 1.01001000100001... has 1, then 01, then 001, then 0001, etc. No repeating pattern → **Non-terminating non-repeating (Irrational) - **Answer:** (a) Terminating, (b) Repeating, (c) Irrational. *Example 2: Write the first 5 decimal digits of \(\sqrt{5}\) if \(\sqrt{5} \approx 2.236067977...\) Solution: - \(\sqrt{5} = 2.236067977...\) - First 5 decimal digits after decimal point: 2, 3, 6, 0, 6 - **Answer:** 2.23606... *Example 3: A student claims that 3.14141414... is an irrational number. Is the student correct? Explain. Solution: - 3.14141414... has a repeating pattern: "14" repeats - The number can be written as a fraction: \(3.\overline{14}\) - Any repeating decimal represents a rational number - **Answer:** No, the student is incorrect because the decimal repeats, so it is rational.

Key Points

  • Irrational numbers have decimal expansions that are non-terminating and non-repeating.
  • Rational numbers either terminate (end) or repeat a pattern.
  • We can only approximate irrational numbers, never write them exactly in decimal form.
  • If a decimal expansion eventually repeats, the number is rational.
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Tap an option to check your answer0 / 4
Q1.$\sqrt a\times\sqrt b=$
Explanation: Product rule.
Q2.$\sqrt8$ simplifies to:
Explanation: $\sqrt{4\cdot2}=2\sqrt2$.
Q3.$\sqrt{\tfrac{9}{16}}=$
Explanation: $\tfrac{\sqrt9}{\sqrt{16}}$.
Q4.Rationalising removes the surd from the:
Explanation: From the denominator.