Number System & Simplification • Topic 6 of 6
Surds & Indices
An index (exponent) tells how many times a base multiplies itself; a surd is an irrational root such as root 2. The laws of indices (product, quotient, power-of-power, zero and negative exponents) turn ugly expressions into simple ones. To rationalise a denominator like 1/(root a + root b), multiply top and bottom by the conjugate (root a - root b). Compare surds by raising both to the LCM of their root orders.
✅ Solved examples
1. Simplify 2^5 x 2^3 / 2^4.
2^(5+3-4) = 2^4 = 16.
2. Evaluate 27^(2/3).
27^(1/3) = 3, then 3^2 = 9.
3. Rationalise 1/(root 3 - 1).
Multiply by (root 3 + 1): (root 3 + 1)/(3 - 1) = (root 3 + 1)/2.
4. Which is larger, cube root of 4 or square root of 3?
Raise both to power 6: (4^(1/3))^6 = 16; (3^(1/2))^6 = 27. So root 3 is larger.
✏️ Practice — try these, take hints as needed
1. Simplify 3^4 / 3^2.
Subtract exponents.
3^2.
—
9
2. Evaluate 16^(3/4).
16^(1/4) = 2.
2^3.
—
8
3. Value of 2^0 + 3^0?
Any non-zero base ^0 = 1.
1 + 1.
—
2
4. Rationalise 5/(root 5).
Multiply by root 5 / root 5.
5 root 5 / 5.
—
root 5
5. Simplify 9^(1/2) x 8^(1/3).
9^(1/2) = 3.
8^(1/3) = 2.
3 x 2.
6
📝 Topic test — 8 questions
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Formula Reference Sheet
This chapter
HCF, LCM & products
| HCF x LCM | HCF(a,b) x LCM(a,b) = a x b |
|---|---|
| Numbers as multiples | a = HCF x m, b = HCF x n with m, n coprime |
| LCM of fractions | LCM = LCM(numerators) / HCF(denominators) |
| HCF of fractions | HCF = HCF(numerators) / LCM(denominators) |
Counting & series
| Sum 1..n | n(n+1)/2 |
|---|---|
| Sum of squares | n(n+1)(2n+1)/6 |
| Number of factors of N = p^a x q^b | (a+1)(b+1) |
| Sum of first n odd numbers | n^2 |
Indices & surds
| Product rule | a^m x a^n = a^(m+n) |
|---|---|
| Power of a power | (a^m)^n = a^(mn) |
| Rationalising | multiply by the conjugate to clear a surd denominator |
SSC reference
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