Trigonometry & Heights / Distances • Topic 3 of 4
Identities
Three Pythagorean identities do most of the simplifying: sin^2 + cos^2 = 1, 1 + tan^2 = sec^2, and 1 + cot^2 = cosec^2. Rearrange them to swap between functions, and use them to prove or evaluate expressions. A common SSC move: replace sec^2 - tan^2 by 1, or 1 - sin^2 by cos^2, to collapse a long expression.
✅ Solved examples
1. Simplify sec^2 A - tan^2 A.
Identity: equals 1.
2. If sin A = 3/5, find sec A.
cos = 4/5, sec = 1/cos = 5/4.
3. Simplify (1 - cos^2 A).
Equals sin^2 A.
4. cosec^2 A - cot^2 A = ?
Identity: equals 1.
✏️ Practice — try these, take hints as needed
1. Simplify 1 - sin^2 A.
Identity.
—
—
cos^2 A
2. 1 + tan^2 A = ?
Identity.
—
—
sec^2 A
3. cos A = 5/13 -> cosec A?
sin = 12/13.
1/sin.
—
13/12
4. sec^2 30 - tan^2 30?
Identity = 1.
—
—
1
5. Simplify sin A cosec A.
cosec = 1/sin.
Product.
—
1
📝 Topic test — 8 questions
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Formula Reference Sheet
This chapter
Ratios & identities
| Basic ratios | sin = opp/hyp, cos = adj/hyp, tan = opp/adj |
|---|---|
| Reciprocals | cosec = 1/sin, sec = 1/cos, cot = 1/tan |
| Pythagorean | sin^2 + cos^2 = 1 |
| Secant | 1 + tan^2 = sec^2 |
| Cosecant | 1 + cot^2 = cosec^2 |
Standard angles & H&D
| sin | 0, 1/2, 1/root2, root3/2, 1 (at 0,30,45,60,90) |
|---|---|
| cos | 1, root3/2, 1/root2, 1/2, 0 |
| tan | 0, 1/root3, 1, root3, undefined |
| Heights & distances | tan(angle of elevation) = height / horizontal distance |
SSC reference
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