Many SSC sums add or change one part of a ratio. Convert the ratio to actual parts with a multiplier, apply the change, and re-read the new ratio. When a quantity is added equally to all parts, the ratio changes; when one part is changed, set up the new equality. Coins/notes problems (a:b:c counts with different denominations) are ratio plus weighting.
✅ Solved examples
1. A sum of 1100 is divided among A, B, C as 2:3:6. Find C share.
11x = 1100 -> x = 100. C = 6x = 600.
2. Two numbers 3:5; if 8 is added to each they become 2:3. Find them.
(3x+8)/(5x+8) = 2/3 -> 9x+24 = 10x+16 -> x = 8. Numbers 24 and 40.
3. A bag has 1-rupee, 2-rupee and 5-rupee coins in the ratio 3:2:1, with a total value of 96 rupees. Find the number of 2-rupee coins.
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