Factorisation • Topic 2 of 3

Factorisation of Trinomials and Difference of Squares

What is Factorisation of Trinomials (Splitting the Middle Term)?

A trinomial of the form ax² + bx + c can be factored by splitting the middle term bx into two terms whose coefficients multiply to ac and add to b.

Steps for Splitting the Middle Term (when a = 1):

  1. Find two numbers whose product = c and sum = b
  2. Rewrite bx as the sum of these two numbers times x
  3. Factor by grouping

Example: x² + 7x + 12

  • Find numbers with product 12 and sum 7 → 3 and 4
  • x² + 3x + 4x + 12
  • x(x + 3) + 4(x + 3) = (x + 3)(x + 4)

What is Difference of Squares?

A difference of two squares is an expression of the form a² - b², which factors as:

\[

a^2 - b^2 = (a - b)(a + b)

\]

Examples:

  • x² - 9 = (x - 3)(x + 3)
  • 4x² - 25 = (2x - 5)(2x + 5)

Important Note: Sum of squares (a² + b²) cannot be factored using real numbers.

Factorising Quadratics ax² + bx + cTo factorise x² + bx + c: find two numbers p, qsuch that p + q = b AND p × q = cExample: Factorise x² + 7x + 12Find p, q:p + q = 7 AND p × q = 12Try pairs:(1,12): sum=13 ✗ (2,6): sum=8 ✗ (3,4): sum=7 ✓Split middle:x² + 3x + 4x + 12Group:x(x+3) + 4(x+3)Factorise:(x+3)(x+4) ← ANSWERWhen a ≠ 1: Factorise 2x² + 7x + 3Find p,q: p+q = 7, p×q = a×c = 2×3 = 6 → p=6, q=12x² + 6x + x + 3 = 2x(x+3) + 1(x+3) = (x+3)(2x+1)
1
Worked Example

Solve a standard problem on Factorisation of Trinomials and Difference of Squares.

Solution

Apply the formula/method shown in the concept section above.

Key Points

  • Understand the definition and properties of Factorisation of Trinomials and Difference of Squares.
  • Study the worked examples and practice similar problems.
  • Always verify your answer using the original conditions.
Tap an option to check your answer0 / 4
Q1.$a^2-b^2=$
Explanation: Difference of squares.
Q2.$x^2+5x+6=$
Explanation: Sum $5$, product $6$.
Q3.$x^2-9=$
Explanation: $3^2=9$.
Q4.To factorise $x^2+bx+c$, find two numbers with sum $b$ and product:
Explanation: Product $c$.