Circles
Circles look intimidating but run on very few formulas, and the GRE tests almost all of them through one idea: everything scales from the radius. Get the radius and you can produce the diameter, the circumference and the area in a single step each. Arcs and sectors add just one move on top — they are the same circle formulas multiplied by the fraction of the full 360° that the central angle covers. Two conventions matter for the GRE specifically: leave answers in terms of π unless a decimal is requested (the on-screen calculator has no π key beyond basic use, and exact answers avoid rounding traps), and remember the figure is not drawn to scale, so never eyeball a radius or assume a chord is a diameter.
Topics
⚡ GRE shortcuts & speed methods
The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.
- Everything flows from the radius: get r, then diameter (2r), circumference (2πr) and area (πr²) each follow in one step.
- Leave answers in terms of π. It is faster, exact, and dodges rounding traps on the basic on-screen calculator.
- Arcs and sectors are just the circle scaled by θ/360. Spot the friendly fractions: 90° = ¼, 120° = ⅓, 60° = 1/6, 180° = ½.
- Double the radius and area quadruples (r is squared) while circumference only doubles — a classic Quantitative Comparison lever.
- Inscribed angle = half the central angle on the same arc; an angle in a semicircle is always 90° (Thales).
- A triangle drawn from the two ends of a diameter is automatically right-angled — reach for the Pythagorean theorem.
⚠️ Common mistakes & traps
GRE is designed so that careless errors here cost you marks. Internalise each trap before the exam.
- Plugging the diameter into a formula that needs the radius (or vice versa) — halve the diameter first for area and πr².
- Confusing arc length (a distance, uses 2πr) with sector area (a region, uses πr²).
- Squaring the radius when finding circumference, or forgetting to square it when finding area.
- Assuming a chord passes through the centre. Only a diameter does, and only if the figure says so — it is not drawn to scale.
- Applying the "half" rule to a central angle. It is the INSCRIBED angle that is half the arc; the central angle equals the arc.
📈 GRE exam insight & question patterns
Quantitative Comparison — circle P has radius r and circle Q has radius 2r. Quantity A: area of Q. Quantity B: four times the area of P. Which is greater?
Equal. Area of Q = π(2r)² = 4πr² = 4 × area of P. Doubling the radius quadruples the area exactly.
A sector has a central angle of 45° in a circle of radius 8. What fraction of the circle is it, and what is its area?
45/360 = 1/8 of the circle; area = ⅛ × π × 64 = 8π.
Numeric Entry — a circle has an area of 36π. Enter its circumference (in terms of π).
r² = 36 → r = 6, so circumference = 2π × 6 = 12π.
A triangle inscribed in a circle has one side equal to the diameter (10) and another side equal to 6. How is the third side found?
The angle opposite the diameter is 90° (Thales), so it is a right triangle: third side = √(10² − 6²) = √64 = 8.
🎴 Flashcards — instant recall
Tap a card to reveal the answer. Drill these until they are automatic.
📌 Quick revision
Chapter test
🏆 Vidaara GRE success checklist
You have truly mastered Circles when you can tick every box below.
- Recall every formula in this chapter without looking them up
- Solve each topic’s practice set with at least 80% accuracy
- Use the chapter shortcuts to cut your solving time in half
- Spot and avoid every common trap listed above
- Score 80%+ on the timed chapter test
📋 Chapter mastery scorecard
Track where you stand. Aim for the target before moving to the next chapter.
| Skill checkpoint | Target |
|---|---|
| Concept theory & formulas understood | 100% |
| Topic practice sets attempted (4 topics) | 4/4 |
| Best topic-test score | — → 80%+ |
| Chapter test score | — → 80%+ |
| Flashcards drilled to instant recall | 8 cards |
Formula Reference Sheet
Circle basics
| Diameter | d = 2r |
|---|---|
| Circumference | C = 2πr = πd |
| Area | A = πr² |
Arcs & sectors (θ = central angle)
| Arc length | (θ / 360) × 2πr |
|---|---|
| Sector area | (θ / 360) × πr² |
Angles in a circle
| Central angle | = measure of the arc it cuts off |
|---|---|
| Inscribed angle | = ½ × its intercepted arc (½ of the central angle on the same arc) |
| Angle in a semicircle | = 90° (diameter subtends a right angle) |