Solving Linear Inequalities
Solving a linear inequality uses the same steps as a linear equation: simplify each side, collect the variable on one side and constants on the other, then divide by the coefficient. As long as you only add, subtract, or multiply/divide by a positive number, the inequality sign stays exactly as it is. The answer is a range, not a single number — 2x + 3 < 11 gives x < 4, meaning every value below 4 works. It helps to picture the solution on a number line: an open circle for strict < or >, a filled circle for ≤ or ≥, with the shading showing the direction. On the GRE you rarely graph, but knowing whether the boundary is included (≤) or excluded (<) matters when a question asks for the largest or smallest integer that satisfies the condition.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Solving rules
| Add / subtract | a < b ⇒ a ± c < b ± c (sign stays) |
|---|---|
| Multiply / divide by positive | a < b, c > 0 ⇒ ac < bc (sign stays) |
| Multiply / divide by negative | a < b, c < 0 ⇒ ac > bc (sign FLIPS) |
Compound & absolute value
| Compound (AND) | a < x < b means a < x and x < b |
|---|---|
| |x| < k (k > 0) | −k < x < k |
| |x| > k (k > 0) | x < −k OR x > k |
| |x − a| < k | a − k < x < a + k |