Descriptive Statistics • Topic 1 of 4

Mean, Median & Mode

The three measures of centre answer three different questions. The mean is the balance point — add every value and divide by how many there are; it uses all the data, which is why a single extreme value drags it. The median is the positional middle: sort the list, then take the middle value (or the average of the two middle values if there is an even count); it ignores how far away the extremes are, so it is stable against outliers. The mode is simply the most frequent value, and a set can have one mode, several, or none. The single most useful GRE fact here is the relationship for skewed data: when a distribution has a long tail to the high side, the mean sits above the median; a long low tail pulls the mean below the median. Always sort before you touch the median — the most common error is reading the middle of the unsorted list.

A dot plot of the data set 4, 8, 8, 10, 15 with a dashed line marking the mean of 9Dot plot: where the mean sits456789101112131415mean = 9Data set: 4, 8, 8, 10, 15

✅ Solved examples

1. Find the mean, median and mode of 4, 8, 8, 10, 15.
Already sorted. Mean = (4+8+8+10+15)/5 = 45/5 = 9. Median = middle value = 8. Mode = 8 (occurs twice). Note the mean (9) exceeds the median (8) because 15 pulls the tail right.
2. The median of 3, 7, x, 12, 18 (already sorted) is 9. Find x.
With 5 values the median is the 3rd, which is x. So x = 9. (Check the sort holds: 7 ≤ 9 ≤ 12, valid.)
3. A data set has 6 values: 2, 5, 5, 9, 11, 14. Find the median.
Even count, so average the 3rd and 4th values: (5 + 9)/2 = 7. The median need not be a value in the set.
4. Quantitative Comparison. List: 10, 12, 12, 20, 46. Quantity A: the mean. Quantity B: the median. Which is greater?
Mean = (10+12+12+20+46)/5 = 100/5 = 20. Median = middle value = 12. Quantity A (20) > Quantity B (12): the high outlier 46 lifts the mean but not the median. Answer: A is greater.

✏️ Practice — try these, take hints as needed

1. Find the mean of 12, 15, 21, 24, 28.
Add all five values.
Sum = 100.
Divide by 5.
20
2. Find the median of 9, 3, 14, 7, 3, 20.
Sort first: 3, 3, 7, 9, 14, 20.
Even count — average the two middle values.
(7 + 9)/2.
8
3. Find the mode of 6, 9, 9, 11, 6, 9, 4.
Count how often each value appears.
9 appears three times; 6 twice.
Most frequent wins.
9
4. A set of 5 numbers has mean 14. Four of them are 10, 12, 16, 20. Find the fifth.
Total must be 14 × 5.
Sum = 70; known four add to 58.
70 − 58.
12
5. For 5, 8, 8, 40, is the mean greater than, less than, or equal to the median?
Median of 4 values = average of 8 and 8.
Mean = 61/4 = 15.25.
Compare 15.25 with 8.
Mean (15.25) is greater than the median (8)

📝 Topic test — 8 questions

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