Averages & Mixtures • Topic 1 of 4

Arithmetic Mean

The arithmetic mean is the sum of the values divided by how many there are. The most useful reframing for the GRE is the reverse: sum = average × count. If six numbers average 15, their total is 90 — and now any question about one missing value, or about what happens when you add a seventh number, becomes simple. A second powerful idea is the deviation view: the mean is the balance point where the amounts above it exactly cancel the amounts below it, so if most values are clustered you can guess-and-adjust from a convenient anchor. For evenly spaced sets (consecutive integers, arithmetic sequences), the mean is just the average of the first and last terms, so the mean of 1 through 99 is (1 + 99)/2 = 50 without any summing. Keep the count honest — "the average of the integers from 1 to 10 inclusive" has 10 terms, not 9.

✅ Solved examples

1. The average of 5 numbers is 24. What is their sum?
Sum = average × count = 24 × 5 = 120.
2. Four test scores are 78, 85, 90 and 83. Find the mean.
Sum = 78 + 85 + 90 + 83 = 336. Mean = 336/4 = 84.
3. The average of 6 numbers is 20. If five of them sum to 105, find the sixth.
Total = 20 × 6 = 120. Sixth = 120 − 105 = 15.
4. Find the average of all integers from 20 to 40 inclusive.
Evenly spaced, so average = (first + last)/2 = (20 + 40)/2 = 30.

✏️ Practice — try these, take hints as needed

1. The average of 8 numbers is 12.5. Find their sum.
sum = average × count.
12.5 × 8.
Multiply.
100
2. Five numbers average 40; four of them sum to 155. Find the fifth.
Total = 40 × 5.
= 200.
200 − 155.
45
3. The mean of 32, 44, x and 50 is 45. Find x.
Sum = 45 × 4 = 180.
32 + 44 + 50 = 126.
x = 180 − 126.
54
4. Find the average of the even integers from 2 to 20 inclusive.
Evenly spaced set.
average = (first + last)/2.
(2 + 20)/2.
11
5. The average age of a family of 5 is 26. A baby of age 0 joins. New average?
Old sum = 26 × 5 = 130.
New count = 6, sum unchanged.
130/6.
≈ 21.67 years

📝 Topic test — 8 questions

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