3-D Figures (Solids)
Three-dimensional figures on the GRE stay refreshingly narrow: rectangular boxes, cubes, and cylinders — no cones, spheres or pyramids, and no trigonometry. Nearly everything reduces to two questions, "how much fits inside" (volume) and "how much surface covers it" (surface area), each with a short formula per shape. The one genuinely 3-D idea worth drilling is the space diagonal of a box, which is just the Pythagorean theorem applied twice and lands as √(l² + w² + h²). Keep cylinder answers in terms of π, watch that every dimension shares the same unit, and — as with all GRE geometry — read the given measurements rather than trusting a figure that is not drawn to scale.
Topics
⚡ GRE shortcuts & speed methods
The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.
- Only three solids appear on the GRE: box, cube and cylinder. Learn their volume and surface-area formulas and you have covered the topic.
- Volume is a product of dimensions (cubic units); surface area is a sum of face areas (square units). Check which the question wants.
- Scale every linear dimension by k and volume scales by k³ — doubling a cube’s edge makes it 8 times bigger.
- The space diagonal of a box is Pythagoras twice: d = √(l² + w² + h²). Look for hidden triples (3-4-12 → 13, 1-2-2 → 3).
- A cube’s space diagonal is just s√3; its face diagonal is s√2.
- Keep cylinder answers in terms of π, and halve a stated diameter before using r in πr²h.
⚠️ Common mistakes & traps
GRE is designed so that careless errors here cost you marks. Internalise each trap before the exam.
- Confusing volume (cubic units, fills the inside) with surface area (square units, covers the outside).
- Scaling volume linearly — doubling a dimension multiplies the volume by 2³ = 8, not by 2.
- Using the diameter as the radius in a cylinder formula. Halve it first.
- Mixing the space diagonal √(l² + w² + h²) with a face diagonal √(l² + w²) — the space diagonal uses all three dimensions.
- Multiplying dimensions given in different units without converting them to a common unit first.
📈 GRE exam insight & question patterns
Quantitative Comparison — cube A has edge 2 and cube B has edge 4. Quantity A: the volume of B. Quantity B: 4 times the volume of A. Which is greater?
Quantity A. B = 4³ = 64, and 4 × A = 4 × 8 = 32. Doubling the edge multiplies volume by 8, not 4, so B is far larger.
A rectangular box is 3 by 4 by 12. What is the longest straight rod that fits inside it?
The space diagonal: √(9 + 16 + 144) = √169 = 13. It is longer than any edge or face diagonal.
Numeric Entry — a cylinder has radius 5 and height 2. Enter its volume in terms of π.
V = πr²h = π × 25 × 2 = 50π.
A cube has a surface area of 54. What is its volume?
6s² = 54 → s² = 9 → s = 3, so volume = 3³ = 27.
🎴 Flashcards — instant recall
Tap a card to reveal the answer. Drill these until they are automatic.
📌 Quick revision
Chapter test
🏆 Vidaara GRE success checklist
You have truly mastered 3-D Figures (Solids) when you can tick every box below.
- Recall every formula in this chapter without looking them up
- Solve each topic’s practice set with at least 80% accuracy
- Use the chapter shortcuts to cut your solving time in half
- Spot and avoid every common trap listed above
- Score 80%+ on the timed chapter test
📋 Chapter mastery scorecard
Track where you stand. Aim for the target before moving to the next chapter.
| Skill checkpoint | Target |
|---|---|
| Concept theory & formulas understood | 100% |
| Topic practice sets attempted (5 topics) | 5/5 |
| Best topic-test score | — → 80%+ |
| Chapter test score | — → 80%+ |
| Flashcards drilled to instant recall | 9 cards |
Formula Reference Sheet
Volume
| Rectangular solid (box) | V = l × w × h |
|---|---|
| Cube, edge s | V = s³ |
| Cylinder | V = πr²h |
Surface area
| Rectangular solid | SA = 2(lw + lh + wh) |
|---|---|
| Cube, edge s | SA = 6s² |
| Cylinder (total) | SA = 2πr² + 2πrh = 2πr(r + h) |
Diagonals
| Space diagonal of a box | d = √(l² + w² + h²) |
|---|---|
| Space diagonal of a cube, edge s | d = s√3 |
| Face diagonal | √(l² + w²) for that face |