Circle, Sector & Segment
A full circle has area πr² and circumference 2πr. A sector is a "pizza slice" subtending angle θ at the centre: its area is the fraction θ/360 of the whole circle, (θ/360)πr², and its arc length is the same fraction of the circumference, (θ/360)·2πr. The perimeter of a sector is that arc plus the two radii: arc + 2r. A segment is the region between a chord and its arc; the minor segment equals the sector minus the triangle formed by the two radii and the chord, so its area is (θ/360)πr² − ½r²·sinθ. CAT loves the clean angles — 60° gives a sixth of the circle, 90° a quarter, 120° a third — so recognise the fraction instantly. Keep answers in terms of π unless a numeric value is demanded; substituting 22/7 or 3.14 too early is the main source of error and wasted time.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Triangle & quadrilateral areas
| Triangle (base–height) | Area = ½ × b × h |
|---|---|
| Triangle (Heron, s = (a+b+c)/2) | Area = √[s(s−a)(s−b)(s−c)] |
| Triangle (two sides + angle) | Area = ½ × a × b × sinC |
| Equilateral triangle (side a) | Area = (√3 / 4) × a² ; height = (√3/2)a |
| Parallelogram / Rhombus | b × h ; rhombus = ½ × d₁ × d₂ |
| Trapezium (parallel sides a, b) | Area = ½ × (a + b) × h |
Circle, sector & segment
| Circle area & circumference | Area = πr² ; Circumference = 2πr |
|---|---|
| Sector area (angle θ°) | (θ/360) × πr² |
| Arc length (angle θ°) | (θ/360) × 2πr |
| Minor segment area | Sector − triangle = (θ/360)πr² − ½r²·sinθ |
| Ring (annulus) area | π(R² − r²) |