Meeting Point
When two bodies move on a circular track of length L, the time to their FIRST meeting depends only on relative speed. Opposite directions: they close the gap at speed (a + b) and meet after covering L between them, so t = L/(a + b). Same direction: the faster gains on the slower at (a − b), and must gain a full lap L before catching up, so t = L/|a − b|. The CAT-smart move is to never plug raw numbers blindly — read the direction first, then pick sum or difference. A useful extra: the position of the first meeting can be found by computing how far the faster (or either) body has run, then taking that distance modulo L from the start. Because the two never stop, every subsequent meeting happens after the SAME time gap, so meetings are equally spaced in time.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Meeting times on a circular track of length L
| Relative speed (opposite directions) | a + b |
|---|---|
| Relative speed (same direction) | |a − b| |
| Time to first meeting (opposite) | L / (a + b) |
| Time to first meeting (same) | L / |a − b| |
| Time for one full lap | L / a and L / b |
Meeting points & return to start
| Distinct meeting points (opposite) | |a + b| / HCF(a, b) |
|---|---|
| Distinct meeting points (same) | |a − b| / HCF(a, b) |
| Time to meet again AT the start | LCM( L/a , L/b ) |
| Same start point as ratio | meet at start after each completes whole laps |
| Three bodies, first meeting | LCM of the pairwise meeting times |