Area Applications • Topic 3 of 3

Paths & Borders

A path or border is a strip of uniform width w running around or inside a figure, or roads crossing a field. The outer-minus-inner principle handles all of it, but two formulas save real time in the exam. An outer path of width w around a rectangle l × b has area (l + 2w)(b + 2w) − lb; the dimensions grow by 2w on each axis because the path is added to both sides. An inner border (a margin inside the figure) shrinks the inner rectangle to (l − 2w)(b − 2w), so its area is lb minus that. For a circular ring or running track of inner radius r and width w, the area is π[(r + w)² − r²] = πw(2r + w). The crossing-roads case is the famous trap: two roads of width w, one along the length and one along the breadth, have combined area lw + bw − w² — you subtract w² because the square where they intersect would otherwise be counted twice. Always decide first whether the strip is added outside or carved inside; that sign error is the single biggest score-killer here.

✅ Solved examples

1. A rectangular garden 30 m by 20 m has a path 2 m wide running all around it on the outside. Find the area of the path.
Outer = (30 + 4)(20 + 4) = 34 × 24 = 816. Garden = 600. Path = 816 − 600 = 216 m².
2. A 2 m wide path is built inside the boundary of a 25 m by 18 m field, along its edges. Find the area of the path.
Inner rectangle = (25 − 4)(18 − 4) = 21 × 14 = 294. Field = 450. Path = 450 − 294 = 156 m².
3. A rectangular field 60 m by 40 m has two roads each 3 m wide, one parallel to the length and one to the breadth, crossing at the middle. Find the total road area.
Road along length = 60 × 3 = 180. Road along breadth = 40 × 3 = 120. Overlap square = 3 × 3 = 9. Total = 180 + 120 − 9 = 291 m².
4. A circular park of radius 21 m has a 7 m wide running track around its outer edge. Find the area of the track (π ≈ 22/7).
Track = πw(2r + w) = (22/7) × 7 × (42 + 7) = 22 × 49 = 1078 m².

✏️ Practice — try these, take hints as needed

1. A garden 40 m by 25 m has a 5 m wide path around it on the outside. Find the path area.
Outer = (l + 2w)(b + 2w).
(50)(35) = 1750.
Subtract 40 × 25 = 1000.
750 m²
2. A 3 m wide path runs inside a 20 m by 16 m plot along its edges. Find the path area.
Inner = (l − 2w)(b − 2w).
(14)(10) = 140.
320 − 140.
180 m²
3. A field 50 m by 30 m has two crossing roads each 4 m wide (one along each dimension). Find the road area.
Area = lw + bw − w².
50 × 4 + 30 × 4.
Subtract 4².
304 m²
4. A circular pond of radius 14 m has a 3.5 m wide path around it. Find the path area (π ≈ 22/7).
Path = πw(2r + w).
(22/7) × 3.5 × (28 + 3.5).
11 × 31.5.
346.5 m²
5. A square lawn of side 24 m has a 2 m wide path all around it on the outside. Find the cost of paving the path at ₹50 per m².
Outer side = 24 + 4 = 28.
Path = 28² − 24² = 784 − 576 = 208.
208 × 50.
₹10,400

📝 Topic test — 8 questions

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