Binomial Theorem • Topic 2 of 4

General Term

The general term is the single most useful formula in the chapter: T(r+1) = nCr · a^(n−r) · b^r. It is the (r+1)th term, so r runs from 0 (first term) to n (last term) — the +1 trips up many students, so anchor it: r = 0 gives the first term, not r = 1. To find a SPECIFIC term, you do not expand anything — you set up the general term and solve for r. For "find the term containing x^k" type questions, collect all powers of x in T(r+1) into a single exponent of x, set that exponent equal to k, and solve for r; then plug r back to read the coefficient. This is the CAT-fast method and it works identically whether a and b are plain numbers, powers of x, or fractions like x/2 and 3/x². Always simplify the combined power of x carefully — that exponent equation is where the marks are won or lost.

✅ Solved examples

1. Find the 4th term in the expansion of (2x + 3)⁶.
4th term ⇒ r = 3. T₄ = 6C3 · (2x)³ · 3³ = 20 · 8x³ · 27 = 4320x³.
2. Find the coefficient of x⁵ in (x + 2)⁸.
T(r+1) = 8Cr · x^(8−r) · 2^r. Need 8−r = 5 ⇒ r = 3. Coefficient = 8C3 · 2³ = 56 · 8 = 448.
3. Find the term containing x⁹ in (x² + 1/x)¹⁵.
T(r+1) = 15Cr · (x²)^(15−r) · (x⁻¹)^r = 15Cr · x^(30−3r). Set 30 − 3r = 9 ⇒ r = 7. Term = 15C7 · x⁹ = 6435 x⁹.
4. Find the coefficient of x in (3x − 2/x)⁵.
T(r+1) = 5Cr · (3x)^(5−r) · (−2/x)^r = 5Cr · 3^(5−r) · (−2)^r · x^(5−2r). Set 5 − 2r = 1 ⇒ r = 2. Coeff = 5C2 · 3³ · (−2)² = 10 · 27 · 4 = 1080.

✏️ Practice — try these, take hints as needed

1. Find the 3rd term in (x + 1)¹⁰.
3rd term ⇒ r = 2.
T₃ = 10C2 · x⁸ · 1².
10C2 = 45.
45x⁸
2. Find the coefficient of x⁴ in (x + 3)⁷.
Need power 4, so 7−r = 4.
r = 3.
7C3 · 3³.
945
3. Find the 5th term of (2 − x)⁶.
r = 4.
6C4 · 2² · (−x)⁴.
15 · 4 · x⁴.
60x⁴
4. Find the term with x⁶ in (x² + 2/x)⁹.
Power = (2)(9−r) − r = 18 − 3r.
Set 18 − 3r = 6.
r = 4, then 9C4 · 2⁴.
2016x⁶
5. Find the coefficient of x⁻² in (x − 1/x)⁸.
Power = (8−r) − r = 8 − 2r.
Set 8 − 2r = −2 ⇒ r = 5.
8C5 · (−1)⁵.
−56

📝 Topic test — 8 questions

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