Surds & Indices • Topic 4 of 4

Radical Simplification

This topic covers de-nesting compound surds and comparing surds without a calculator. A compound surd √(a ± 2√b) can often be written as √x ± √y, where x + y = a and xy = b — find two numbers that add to a and multiply to b. For example √(7 + 2√12): need x + y = 7, xy = 12, so x = 4, y = 3, giving √4 + √3 = 2 + √3. If the surd reads √(a ± √b) with no 2 in front, first rewrite it as √(a ± 2√(b/4)) to match the template. To compare surds of different orders, raise both to the LCM of their root indices: ∛2 versus √3 becomes, raising to the 6th power, 2^2 = 4 versus 3^3 = 27, so √3 is larger. To compare same-order surds, just compare the radicands. These two skills — de-nesting and ranking — are exactly what CAT tests when surds show up.

✅ Solved examples

1. Simplify √(7 + 2√12).
Need x + y = 7, xy = 12 ⇒ x = 4, y = 3. So √(7 + 2√12) = √4 + √3 = 2 + √3.
2. Simplify √(9 − 2√14).
Need x + y = 9, xy = 14 ⇒ x = 7, y = 2. So √(9 − 2√14) = √7 − √2.
3. Which is greater, ∛2 or √3?
Raise both to the 6th power: (∛2)^6 = 2^2 = 4; (√3)^6 = 3^3 = 27. Since 27 > 4, √3 > ∛2.
4. Simplify √(3 + √5).
Write as √[(6 + 2√5)/2] = √(6 + 2√5)/√2. Now 6 + 2√5 has x + y = 6, xy = 5 ⇒ √5 + 1. So result = (√5 + 1)/√2 = (√10 + √2)/2.

✏️ Practice — try these, take hints as needed

1. Simplify √(11 + 2√30).
Find x + y = 11, xy = 30.
x = 6, y = 5.
Answer is √x + √y.
√6 + √5
2. Simplify √(8 − 2√15).
x + y = 8, xy = 15.
x = 5, y = 3.
Take √x − √y.
√5 − √3
3. Which is greater, ∛3 or ⁴√5?
LCM of 3 and 4 is 12.
(∛3)^12 = 3^4 = 81; (⁴√5)^12 = 5^3 = 125.
Compare 81 vs 125.
⁴√5
4. Simplify √(12 + 2√35).
x + y = 12, xy = 35.
x = 7, y = 5.
√x + √y.
√7 + √5
5. Arrange in ascending order: √2, ∛3, ⁶√10.
Use LCM of indices = 6.
√2 = ⁶√8, ∛3 = ⁶√9, ⁶√10 stays.
Compare radicands 8, 9, 10.
√2 < ∛3 < ⁶√10

📝 Topic test — 8 questions

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