Pythagoras
In a right triangle the square on the hypotenuse equals the sum of the squares on the other two sides: a² + b² = c², where c is the hypotenuse. The fastest CAT students never crunch the algebra — they recognise the standard Pythagorean triples on sight: 3-4-5, 5-12-13, 8-15-17, 7-24-25, and 9-40-41, together with every multiple (6-8-10, 9-12-15, 10-24-26, and so on). Spotting that 39 and 52 are 3 × 13 and 4 × 13 instantly gives a hypotenuse of 65. The converse is equally useful: if a² + b² = c² the triangle is right-angled, while a² + b² > c² makes it acute and a² + b² < c² obtuse, which lets you classify a triangle from its sides alone. Two special right triangles recur constantly: the 45-45-90 with sides in ratio 1 : 1 : √2, and the 30-60-90 with sides in ratio 1 : √3 : 2 — memorise both, because hexagons, equilateral triangles and squares cut along a diagonal all produce them.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Sides, area & similarity
| Angle sum / exterior angle | A + B + C = 180°; exterior = sum of two remote interior angles |
|---|---|
| Triangle inequality | |b − c| < a < b + c |
| Basic area | Area = ½ × base × height |
| Heron’s formula | Area = √[s(s−a)(s−b)(s−c)], s = (a+b+c)/2 |
| Similar triangles (AA) | Area ratio = (corresponding side ratio)² |
| Basic Proportionality (Thales) | DE ∥ BC ⇒ AD/DB = AE/EC |
Right triangles & centres
| Pythagoras | hypotenuse² = leg₁² + leg₂² (a² + b² = c²) |
|---|---|
| Common triples | 3-4-5, 5-12-13, 8-15-17, 7-24-25 (and multiples) |
| Centroid divides median | 2 : 1 from the vertex |
| Circumradius | R = abc / (4 × Area) |
| Inradius | r = Area / s, so Area = r × s |
| Equilateral (side a) | Area = (√3/4)a²; R = a/√3; r = a/(2√3) |