Shaded Regions
Shaded-region problems look intimidating because the wanted area is irregular, but almost all of them collapse to one principle: shaded = outer area − inner area. A circle inscribed in a square, a square inside a circle, four corner circles inside a rectangle, a flower-petal pattern — in each case the shaded part is what remains after you subtract one neat region from another. The two recurring CAT setups are worth memorising. For a circle inscribed in a square of side a, the corners left over total a² − π(a/2)² = a²(1 − π/4) ≈ 0.215a². For a square inscribed in a circle of radius r, the square has diagonal 2r so its side is r√2 and area 2r², leaving the four segments. When overlapping circles create lens or petal shapes, build them from sectors minus triangles. The discipline is to name the outer region, name the inner region, and never lose track of which one is shaded.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Base area formulas
| Rectangle | A = length × breadth |
|---|---|
| Triangle | A = ½ × base × height |
| Circle / ring | A = πr²; ring = π(R² − r²) |
| Trapezium | A = ½ × (sum of parallel sides) × height |
| Sector of a circle | A = (θ/360) × πr² |
Composite & path tools
| Shaded region | A(shaded) = A(outer) − A(inner) |
|---|---|
| Outer border, width w (rectangle l×b) | A = (l + 2w)(b + 2w) − lb |
| Inner border, width w | A = lb − (l − 2w)(b − 2w) |
| Two crossing roads, width w (field l×b) | A = lw + bw − w² |
| Circular ring / track, width w | A = π[(r + w)² − r²] = πw(2r + w) |