Linear Equations • Topic 3 of 4

Simultaneous Equations

A pair of linear equations represents two straight lines, and the number of solutions is just how those lines sit. Compare the coefficient ratios a₁/a₂, b₁/b₂ and c₁/c₂. If a₁/a₂ ≠ b₁/b₂ the lines cross once, giving exactly one (unique) solution — the consistent and independent case. If a₁/a₂ = b₁/b₂ but this differs from c₁/c₂, the lines are parallel and never meet, so there is no solution (inconsistent). If all three ratios are equal, the equations are really the same line written twice, so there are infinitely many solutions (dependent). A quick equivalent for the unique case is the determinant D = a₁b₂ − a₂b₁ ≠ 0. CAT loves the "find k" version: it gives a parameter inside the coefficients and asks for the value that makes the system have no solution or infinitely many. The drill is to set the matching ratios equal, solve for k, then check the c-ratio to decide which case you have landed in.

✅ Solved examples

1. Does 2x + 3y = 7 and 4x + 6y = 14 have a unique, no, or infinite solution?
Ratios: 2/4 = 3/6 = 7/14 = 1/2. All equal ⇒ same line ⇒ infinitely many solutions.
2. Classify x + 2y = 5 and 2x + 4y = 9.
a₁/a₂ = 1/2, b₁/b₂ = 2/4 = 1/2, c₁/c₂ = 5/9. First two equal but ≠ 5/9 ⇒ parallel ⇒ no solution.
3. For what value of k do 2x + 3y = 8 and 4x + ky = 16 have infinitely many solutions?
Need all three ratios equal: 2/4 = 3/k = 8/16. Since 2/4 = 1/2 = 8/16, set 3/k = 1/2 ⇒ k = 6. So k = 6.
4. For what value of k does 3x − ky = 7 and 6x − 4y = 13 have no solution?
Parallel needs a₁/a₂ = b₁/b₂ ≠ c₁/c₂. 3/6 = (−k)/(−4) ⇒ 1/2 = k/4 ⇒ k = 2. Check c: 7/13 ≠ 1/2, holds ⇒ k = 2.

✏️ Practice — try these, take hints as needed

1. Classify 3x + 2y = 6 and 6x + 4y = 18.
Compare a₁/a₂, b₁/b₂, c₁/c₂.
3/6 = 2/4 = 1/2.
6/18 = 1/3, which differs.
No solution (parallel lines)
2. Classify x − y = 3 and 2x + y = 9.
Compute a₁/a₂ and b₁/b₂.
1/2 vs (−1)/1.
Ratios differ.
Unique solution
3. For what k do 2x + 3y = 4 and 4x + 6y = k have infinitely many solutions?
Need all three ratios equal.
2/4 = 3/6 = 1/2.
So 4/k = 1/2.
k = 8
4. For what k does kx + 2y = 5 and 6x + 4y = 9 have no solution?
Set a₁/a₂ = b₁/b₂.
k/6 = 2/4 = 1/2.
Check c-ratio ≠ this.
k = 3
5. Is x + 2y = 4 and 3x + 6y = 12 consistent? How many solutions?
Compare all three ratios.
1/3 = 2/6 = 4/12.
All equal.
Infinitely many solutions

📝 Topic test — 8 questions

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