Geometric Progression • Topic 1 of 3

nth Term

The nth term of a GP is a_n = a·r^(n−1), where a is the first term and r the common ratio. The exponent is (n−1), not n — the first term carries no factor of r, the second carries r¹, and so on. This single formula lets you jump straight to the 15th or 50th term without writing the whole sequence. The CAT-smart move is to work with ratios of terms: a_m/a_n = r^(m−n), which kills the unknown a. If the 4th term is 24 and the 7th is 192, then a_7/a_4 = r³ = 192/24 = 8, so r = 2 in one line. To check whether three numbers are in GP, test whether the middle term squared equals the product of the outers (b² = ac); this is also how you spot the geometric mean. Watch the sign of r: a negative ratio makes the terms alternate in sign, a trap CAT exploits.

✅ Solved examples

1. Find the 6th term of the GP 5, 10, 20, ...
a = 5, r = 2. a_6 = 5·2^(6−1) = 5·32 = 160.
2. The 3rd term of a GP is 18 and the 6th is 486. Find r.
a_6/a_3 = r³ = 486/18 = 27 ⇒ r = 3.
3. For which n is the nth term of 2, 6, 18, ... equal to 1458?
a = 2, r = 3. 2·3^(n−1) = 1458 ⇒ 3^(n−1) = 729 = 3⁶ ⇒ n−1 = 6 ⇒ n = 7.
4. In a GP the 2nd term is 6 and the 5th term is 48. Find the first term.
a_5/a_2 = r³ = 48/6 = 8 ⇒ r = 2. a_2 = a·r = 6 ⇒ a = 6/2 = 3.

✏️ Practice — try these, take hints as needed

1. Find the 8th term of the GP 3, 6, 12, ...
a = 3, r = 2.
a_8 = a·r^7.
3 × 128.
384
2. The 4th term of a GP is 40 and the 6th is 160. Find r (r > 0).
a_6/a_4 = r².
160/40 = 4.
Take the positive root.
2
3. Which term of 1, 3, 9, ... equals 2187?
a = 1, r = 3.
3^(n−1) = 2187.
2187 = 3^7.
8th term (n = 8)
4. The 2nd term of a GP is 12 and the 4th is 48. Find the first term (r > 0).
a_4/a_2 = r² = 4.
r = 2.
a·r = 12.
6
5. Three numbers x, 12, 27 are in GP. Find x.
Middle² = product of outers.
12² = x·27.
144/27.
16/3

📝 Topic test — 8 questions

Auto-graded with full solutions; saved to your dashboard. Use the calculator and formula sheet (top-right) any time.

Loading questions…