Crossing a Point
A "point" has no length — a pole, a signal post, a standing man, the edge of a platform. To cross it, the train covers exactly its OWN length, because the engine reaches the point first and the last coach clears it last. So time = length ÷ speed, and equivalently length = speed × time. The one habit that separates fast solvers from slow ones is the unit switch: speeds in CAT come in km/h but lengths come in metres, so convert km/h to m/s by multiplying by 5/18 before you divide. A clean check: a train at 72 km/h moves at 72 × 5/18 = 20 m/s, so a 200 m train clears a pole in 200 ÷ 20 = 10 s. Memorise that 18 km/h = 5 m/s, 36 = 10, 54 = 15, 72 = 20, 90 = 25 — those five conversions cover most questions instantly.
✅ Solved examples
✏️ Practice — try these, take hints as needed
📝 Topic test — 8 questions
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Formula Reference Sheet
Core relations
| Crossing a point (pole/man/signal) | time = train length ÷ speed |
|---|---|
| Crossing a platform/bridge | time = (train length + platform length) ÷ speed |
| km/h to m/s | multiply by 5/18 |
| m/s to km/h | multiply by 18/5 |
| Speed | speed = distance ÷ time |
Two bodies in motion
| Relative speed — opposite directions | add the two speeds |
|---|---|
| Relative speed — same direction | subtract (faster − slower) |
| Two trains crossing each other | time = (L₁ + L₂) ÷ relative speed |
| Train crossing a moving man/train | distance = sum of relevant lengths, speed = relative |
| Two crossing times → lengths | use point-time × speed = own length |