CAT Quant · Study & Practice

Circles

AreaGeometry DifficultyModerate–Hard CAT weightage1–3 questions (Geometry/Mensuration; often paired with triangles, coordinate geometry)

Circles are the backbone of CAT Geometry. Almost every hard geometry question in CAT, XAT and SNAP leans on a small bundle of circle facts — a chord, a tangent, an inscribed angle, a cyclic quadrilateral — and the candidates who clear the 95+ percentile are simply the ones who recognise which fact applies in two seconds. The beauty of this chapter is that you do not need many theorems; you need to wield about nine of them with total confidence. The perpendicular from the centre bisects a chord, equal chords sit equidistant from the centre, a tangent meets the radius at 90°, the two tangents from an external point are equal, the power of a point ties intersecting chords and secants together, the alternate segment theorem links a tangent to the inscribed angle, opposite angles of a cyclic quadrilateral are supplementary, and the angle at the centre is twice the angle at the circumference. This chapter walks through each with CAT-style worked problems, the fastest recognition cues, and the traps that quietly drain marks. Master these and circle questions flip from intimidating to free.

Topics

⚡ CAT shortcuts & speed methods

The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.

  • For any chord problem, drop the perpendicular from the centre and use chord = 2√(r² − d²) — it converts the figure into one right triangle.
  • Tangent length from an external point P is √(OP² − r²); the radius-to-tangent 90° is your built-in right angle.
  • Power of a point unifies three cases: chords PA×PB = PC×PD, secants PA×PB = PC×PD, tangent–secant PT² = PA×PB.
  • See a diameter? Mark 90° at any third point instantly (angle in a semicircle).
  • Angle at centre = 2 × angle at circumference; angles in the same segment are equal — use them to migrate a known angle across the circle.
  • Tangent meets a chord? Apply the alternate segment theorem at once: that angle equals the inscribed angle across the circle.

⚠️ Common mistakes & traps

CAT is designed so that careless errors here cost you marks. Internalise each trap before the exam.

  • Using the full chord instead of the half-chord in chord = 2√(r² − d²) — d, the half-chord, and r form the right triangle, not the full chord.
  • Adding chord distances when the chords are on opposite sides but subtracting requires the same side (and vice versa).
  • Writing PT = √(OP² + r²) instead of √(OP² − r²) — the radius is a leg, OP is the hypotenuse.
  • Forgetting that opposite (not adjacent) angles of a cyclic quadrilateral are supplementary.
  • Doubling the inscribed angle to get the central angle but then doubling again, or halving the wrong way — central is the larger (2×).

📈 CAT exam insight & PYQ analysis

In CAT, pure-circle questions are less frequent than triangles but reliably appear once or twice, usually fused with triangles, coordinate geometry or mensuration. The recurring patterns are: tangent length and the power-of-a-point relations (especially PT² = PA × PB), chord-distance Pythagoras setups, the angle-in-a-semicircle right angle hidden inside a larger figure, and cyclic-quadrilateral angle chases. XAT and SNAP lean slightly more on the inscribed-angle and alternate-segment results. The difficulty is Moderate–Hard, and the marks usually go to candidates who can quickly identify which circle theorem the figure is quietly invoking rather than to those who compute the most.

🎴 Flashcards — instant recall

Tap a card to reveal the answer. Drill these until they are automatic.

Chord length given distance d from centre?Tap to reveal
2√(r² − d²)
Perpendicular from centre to a chord does what?Tap to reveal
Bisects the chord
Equal chords are __ from the centre?Tap to reveal
Equidistant
Tangent meets the radius at what angle?Tap to reveal
90°
Tangent length from external point P?Tap to reveal
√(OP² − r²)
Two tangents from one external point are?Tap to reveal
Equal in length
Tangent–secant power of a point?Tap to reveal
PT² = PA × PB
Intersecting chords relation?Tap to reveal
PA × PB = PC × PD
Angle in a semicircle?Tap to reveal
90°
Angle at centre vs at circumference (same arc)?Tap to reveal
Centre = 2 × circumference
Cyclic quadrilateral opposite angles?Tap to reveal
Supplementary (sum to 180°)
Alternate segment theorem says?Tap to reveal
Tangent–chord angle = inscribed angle in the alternate segment

📌 Quick revision

Circles run on about nine facts. The perpendicular from the centre bisects a chord, giving chord = 2√(r² − d²), and equal chords are equidistant from the centre. A tangent is perpendicular to the radius, the tangent length from an external point is √(OP² − r²), and the two tangents from a point are equal. Power of a point ties it together: PA × PB = PC × PD for chords/secants and PT² = PA × PB for a tangent–secant. For angles: the central angle is twice the inscribed angle on the same arc, the angle in a semicircle is 90°, opposite angles of a cyclic quadrilateral are supplementary, and the alternate segment theorem equates a tangent–chord angle to the inscribed angle across the circle. Recognise the theorem first; the arithmetic is usually short.

Chapter test

🏆 Vidaara CAT success checklist

You have truly mastered Circles when you can tick every box below.

  • Recall every formula in this chapter without looking them up
  • Solve each topic’s practice set with at least 80% accuracy
  • Use the chapter shortcuts to cut your solving time in half
  • Spot and avoid every common trap listed above
  • Score 80%+ on the timed chapter test

📋 Chapter mastery scorecard

Track where you stand. Aim for the target before moving to the next chapter.

Skill checkpointTarget
Concept theory & formulas understood100%
Topic practice sets attempted (4 topics)4/4
Best topic-test score— → 80%+
Chapter test score— → 80%+
Flashcards drilled to instant recall12 cards