CAT Quant · Study & Practice

Factors

AreaNumber System DifficultyModerate CAT weightage1–3 questions (directly + inside HCF/LCM, divisibility and number-property sets)

Factors sit at the heart of CAT Number System, and almost every "how many", "what is the sum", or "in how many ways" question about a number traces back to one idea: its prime factorisation. Once you write a number as N = p^a × q^b × r^c, everything about its divisors becomes a counting exercise rather than a listing exercise. You never write out all the factors of 720 — you read them off its prime powers. This chapter builds that fluency: the number-of-factors formula (a+1)(b+1)(c+1), the sum-of-factors product formula, the elegant product-of-factors result N^(d/2), the number of ways to split N into two factors, and the high-yield variations CAT loves — counting only even factors, only odd factors, factors that are perfect squares, or factors divisible by a given number. The same machinery answers "how many divisors are multiples of 6" and "how many ordered pairs (a, b) satisfy a × b = N". Master the prime-factorisation reflex first; every formula here is just a different way of counting what that factorisation already encodes. We keep the India-context CAT/XAT/SNAP framing throughout, favouring the fast structural method over brute listing.

Topics

⚡ CAT shortcuts & speed methods

The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.

  • Always start by writing the prime factorisation N = p^a × q^b × r^c — every divisor question is then pure counting.
  • Number of factors = (a+1)(b+1)(c+1). Odd factors: drop the power of 2. Even factors: total − odd.
  • Sum of factors σ(N) = product of GP sums (1 + p + ... + p^a) per prime. Sum of reciprocals of factors = σ(N)/N.
  • Product of all factors = N^(d/2). To find d from the product: if product = N^k then d = 2k.
  • Ways to write N as a product of two factors = d/2, but (d+1)/2 when N is a perfect square (odd d signals a perfect square).
  • For "factors divisible by m" with m | N, count the factors of N/m. For "perfect-square factors", use ⌊exponent/2⌋ + 1 per prime.

⚠️ Common mistakes & traps

CAT is designed so that careless errors here cost you marks. Internalise each trap before the exam.

  • Forgetting the "+1" in (a+1)(b+1)(c+1) — the exponents themselves do not count the choice of zero copies (which keeps 1 in).
  • Adding the prime-power sums instead of multiplying them when computing σ(N).
  • Using d/2 for the number of two-factor products when N is a perfect square — it must be (d+1)/2 there.
  • Counting even factors as "total minus 1" instead of total minus the odd-factor count.
  • Treating the product of factors as N^d instead of N^(d/2) — each pair multiplies to N, and there are only d/2 pairs.

📈 CAT exam insight & PYQ analysis

In CAT and XAT, factor questions seldom stand alone; they hide inside number-property, HCF/LCM and remainder sets, or appear as "how many ordered pairs", "how many divisors of N are perfect squares", or "in how many ways can N be expressed as a product of two co-prime factors". The recurring high-value patterns are the (a+1)(b+1)(c+1) count with an added condition (even/odd/divisible-by-m), the product-of-factors = N^(d/2) reversal, and the perfect-square edge case in two-factor counting. Difficulty is Moderate: the formula is short, but the conditioned variants and the perfect-square subtlety separate a 95-percentiler from a 99-percentiler.

🎴 Flashcards — instant recall

Tap a card to reveal the answer. Drill these until they are automatic.

Number of factors of N = p^a × q^b × r^c?Tap to reveal
(a+1)(b+1)(c+1)
Sum of factors formula?Tap to reveal
σ(N) = Π (p^(a+1) − 1)/(p − 1)
Product of all factors of N?Tap to reveal
N^(d/2), d = number of factors
Ways to write N as a product of two factors (N not a perfect square)?Tap to reveal
d/2
Ways to write N as a product of two factors (N a perfect square)?Tap to reveal
(d+1)/2
How to count only the odd factors?Tap to reveal
Drop the power of 2; multiply (exponent+1) for odd primes
How to count only the even factors?Tap to reveal
Total factors − odd factors
A number with exactly 3 factors is always?Tap to reveal
The square of a prime
Sum of all factors of 12?Tap to reveal
28
Product of all factors of 12?Tap to reveal
12^3 = 1728
Sum of reciprocals of all factors of N?Tap to reveal
σ(N)/N
If the product of factors of N is N^4, how many factors?Tap to reveal
8

📌 Quick revision

Factorise first: N = p^a × q^b × r^c. The number of factors is (a+1)(b+1)(c+1); the sum is the product of each prime’s GP sum, σ(N) = Π(p^(a+1) − 1)/(p − 1); the product of all factors is N^(d/2). Count odd factors by dropping the 2; even factors as total minus odd; perfect-square factors with ⌊exponent/2⌋ + 1. The number of ways to write N as a product of two factors is d/2, but (d+1)/2 when N is a perfect square. Remember the "+1", multiply (don’t add) for σ, and watch the perfect-square edge case.

Chapter test

🏆 Vidaara CAT success checklist

You have truly mastered Factors when you can tick every box below.

  • Recall every formula in this chapter without looking them up
  • Solve each topic’s practice set with at least 80% accuracy
  • Use the chapter shortcuts to cut your solving time in half
  • Spot and avoid every common trap listed above
  • Score 80%+ on the timed chapter test

📋 Chapter mastery scorecard

Track where you stand. Aim for the target before moving to the next chapter.

Skill checkpointTarget
Concept theory & formulas understood100%
Topic practice sets attempted (3 topics)3/3
Best topic-test score— → 80%+
Chapter test score— → 80%+
Flashcards drilled to instant recall12 cards