Polynomials
Polynomials sit quietly behind a large slice of CAT Algebra. A polynomial is just an expression built from a variable using addition, subtraction and whole-number powers — and almost every quadratic, cubic, identity-based simplification or roots question is really a polynomials question wearing a different label. CAT rarely asks you to "expand (a+b)³" in the open; instead it hides the algebraic identities inside ugly-looking arithmetic (compute 103³ in your head), buries the factor theorem inside a divisibility problem, or asks for the sum of cubes of the roots of a cubic without ever solving it. The students who score here are the ones who recognise the standard forms instantly and reach for the right tool — an identity, the remainder theorem, the factor theorem, or Vieta’s relations — instead of grinding. This chapter builds that pattern-recognition: the core identities for squares and cubes, the remainder and factor theorems for division, and the symmetric-function relations that connect the coefficients of a polynomial to its roots. Each topic carries worked CAT-style examples, the fastest line of attack, and the traps that quietly cost marks.
Topics
⚡ CAT shortcuts & speed methods
The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.
- Read ugly numbers as identities: 103² = (100+3)², 97×103 = (100−3)(100+3) = 10000 − 9.
- x + 1/x given ⇒ x² + 1/x² = (x + 1/x)² − 2 and x³ + 1/x³ = (x + 1/x)³ − 3(x + 1/x).
- a + b + c = 0 is a gift: it forces a³ + b³ + c³ = 3abc instantly.
- Factor theorem: to factor a cubic, test divisors of the constant term; (x − 1) works when coefficients sum to 0.
- Remainder of P(x) ÷ (x − a) is just P(a) — never do long division in the exam.
- For roots, use Vieta first: Σα = −b/a, Σαβ = c/a, αβγ = −d/a; then Σα² = (Σα)² − 2Σαβ.
⚠️ Common mistakes & traps
CAT is designed so that careless errors here cost you marks. Internalise each trap before the exam.
- Dropping the middle term: (a + b)² is a² + 2ab + b², not a² + b².
- Sign slips in Vieta — forgetting product of roots of a cubic is −d/a, not d/a.
- Using x = a (not x = −a) when dividing by (x + a) in the remainder theorem.
- Misremembering a³ − b³ = (a − b)(a² + ab + b²): the middle sign is +, opposite to the binomial’s.
- Assuming a + b + c = 0 makes a³ + b³ + c³ = 0; it equals 3abc, not 0.
📈 CAT exam insight & PYQ analysis
🎴 Flashcards — instant recall
Tap a card to reveal the answer. Drill these until they are automatic.
📌 Quick revision
Chapter test
🏆 Vidaara CAT success checklist
You have truly mastered Polynomials when you can tick every box below.
- Recall every formula in this chapter without looking them up
- Solve each topic’s practice set with at least 80% accuracy
- Use the chapter shortcuts to cut your solving time in half
- Spot and avoid every common trap listed above
- Score 80%+ on the timed chapter test
📋 Chapter mastery scorecard
Track where you stand. Aim for the target before moving to the next chapter.
| Skill checkpoint | Target |
|---|---|
| Concept theory & formulas understood | 100% |
| Topic practice sets attempted (4 topics) | 4/4 |
| Best topic-test score | — → 80%+ |
| Chapter test score | — → 80%+ |
| Flashcards drilled to instant recall | 12 cards |
Formula Reference Sheet
Algebraic identities
| Square of a sum/difference | (a ± b)² = a² ± 2ab + b² |
|---|---|
| Difference of squares | a² − b² = (a − b)(a + b) |
| Cube of a sum/difference | (a ± b)³ = a³ ± 3a²b + 3ab² ± b³ |
| Sum/difference of cubes | a³ ± b³ = (a ± b)(a² ∓ ab + b²) |
| Three-cube identity | a³ + b³ + c³ − 3abc = (a + b + c)(a² + b² + c² − ab − bc − ca) |
| Square of a trinomial | (a + b + c)² = a² + b² + c² + 2(ab + bc + ca) |
Division & roots tools
| Remainder theorem | Remainder of P(x) ÷ (x − a) is P(a) |
|---|---|
| Factor theorem | (x − a) divides P(x) ⇔ P(a) = 0 |
| Vieta — quadratic ax²+bx+c | sum = −b/a, product = c/a |
| Vieta — cubic ax³+bx²+cx+d | Σα = −b/a, Σαβ = c/a, αβγ = −d/a |
| Sum of squares of roots | Σα² = (Σα)² − 2Σαβ |
| When a+b+c = 0 | a³ + b³ + c³ = 3abc |