Trains
Trains problems are Time-Speed-Distance (TSD) questions with one extra idea: a train has length, so the distance it must travel to "cross" something is not zero. To pass a stationary point — a pole, a man standing on a platform, a signal post — the train must move its own length, because the engine reaches the point first and the guard’s coach leaves it last. To cross a platform, a bridge or a tunnel, it must cover its own length PLUS the length of that object. When two trains cross each other, the distance covered is the SUM of their lengths, and the speed that matters is their relative speed — the sum of speeds if they move in opposite directions, the difference if they move the same way. That single relative-speed idea, paired with the constant 5/18 to switch km/h to m/s, solves almost every train question CAT or XAT throws at you. This chapter builds the three core cases in order — crossing a point, crossing a platform, two trains crossing — each with the fast multiplier method, worked examples and the traps that cost careless students a clean mark.
Topics
⚡ CAT shortcuts & speed methods
The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.
- Crossing a POINT means crossing your own length; crossing a PLATFORM means own length + platform length. Decide which before writing an equation.
- Memorise km/h → m/s pegs: 18=5, 36=10, 54=15, 72=20, 90=25, 108=30. Multiply any speed by 5/18 to switch.
- Two trains: distance is always L₁ + L₂. Opposite ⇒ ADD speeds, same direction ⇒ SUBTRACT.
- Given pole-time t₁ and platform-time t₂ at the same speed: platform length = speed × (t₂ − t₁), and speed = length ÷ t₁.
- Two crossing times (opposite t_o, same t_s) for the same pair: sum of speeds = (L₁+L₂)/t_o, difference = (L₁+L₂)/t_s; then split.
- A man/pole is a point (length 0). A bridge/tunnel/platform is a length — never treat them the same way.
⚠️ Common mistakes & traps
CAT is designed so that careless errors here cost you marks. Internalise each trap before the exam.
- Forgetting to add the platform length — using only the train’s length to cross a platform.
- Mixing units: dividing a length in metres by a speed in km/h without the 5/18 conversion.
- Adding speeds for same-direction overtaking (should subtract) or subtracting for opposite directions (should add).
- Using only ONE train’s length when two trains cross — the distance is the SUM of both lengths.
- Treating a moving man as a point but forgetting his speed adds to or subtracts from the train’s relative speed.
📈 CAT exam insight & PYQ analysis
🎴 Flashcards — instant recall
Tap a card to reveal the answer. Drill these until they are automatic.
📌 Quick revision
Chapter test
🏆 Vidaara CAT success checklist
You have truly mastered Trains when you can tick every box below.
- Recall every formula in this chapter without looking them up
- Solve each topic’s practice set with at least 80% accuracy
- Use the chapter shortcuts to cut your solving time in half
- Spot and avoid every common trap listed above
- Score 80%+ on the timed chapter test
📋 Chapter mastery scorecard
Track where you stand. Aim for the target before moving to the next chapter.
| Skill checkpoint | Target |
|---|---|
| Concept theory & formulas understood | 100% |
| Topic practice sets attempted (3 topics) | 3/3 |
| Best topic-test score | — → 80%+ |
| Chapter test score | — → 80%+ |
| Flashcards drilled to instant recall | 12 cards |
Formula Reference Sheet
Core relations
| Crossing a point (pole/man/signal) | time = train length ÷ speed |
|---|---|
| Crossing a platform/bridge | time = (train length + platform length) ÷ speed |
| km/h to m/s | multiply by 5/18 |
| m/s to km/h | multiply by 18/5 |
| Speed | speed = distance ÷ time |
Two bodies in motion
| Relative speed — opposite directions | add the two speeds |
|---|---|
| Relative speed — same direction | subtract (faster − slower) |
| Two trains crossing each other | time = (L₁ + L₂) ÷ relative speed |
| Train crossing a moving man/train | distance = sum of relevant lengths, speed = relative |
| Two crossing times → lengths | use point-time × speed = own length |