Triangles
Triangles are the load-bearing wall of CAT Geometry. Almost every other geometry result — properties of circles, polygons, coordinate geometry, even mensuration of 3-D solids — is ultimately built on a triangle drawn inside the figure, so the student who is fluent here clears the whole domain faster. CAT does not ask you to recite the angle-sum property; it hides a 30-60-90 triangle inside a hexagon, or asks for a ratio of areas that only the similarity rule unlocks. This chapter develops the four ideas the exam actually tests: congruence (proving two triangles are identical so a length or angle transfers), similarity and the (side ratio)² area rule that is the single highest-yield shortcut in the section, the Pythagoras theorem with its recurring triples, and the four classical centres — centroid, incentre, circumcentre and orthocentre — together with the two area links R = abc/(4·Area) and Area = r·s. Each topic comes with worked CAT-style examples, the fastest method, and the specific traps that cost careless aspirants a clean two marks.
Topics
⚡ CAT shortcuts & speed methods
The fastest ways to crack this chapter under time pressure — the techniques that separate a 95+ percentiler from the rest.
- Spot Pythagorean triples on sight — 3-4-5, 5-12-13, 8-15-17, 7-24-25, 9-40-41 and all multiples — to skip square-root work.
- For similar triangles: sides, perimeters, medians and radii scale by k; areas scale by k². Square the side ratio for areas.
- Any line parallel to a side (Thales/BPT) instantly splits the other two sides in equal ratio — use it whenever you see ∥ marks.
- Right-triangle circumradius is just half the hypotenuse; no need for R = abc/(4·Area).
- Memorise the two special triangles: 45-45-90 → 1 : 1 : √2 and 30-60-90 → 1 : √3 : 2.
- Use Area = r·s to get the inradius and R = abc/(4·Area) for the circumradius once Heron’s area is known.
⚠️ Common mistakes & traps
CAT is designed so that careless errors here cost you marks. Internalise each trap before the exam.
- Treating SSA or AAA as a congruence test — SSA is ambiguous and AAA gives similarity only.
- Using the side ratio for the area of similar triangles instead of its square (k vs k²).
- Mislabelling the hypotenuse — Pythagoras only works with c as the side opposite the right angle.
- Splitting the median in the wrong direction — the 2 : 1 part is from the VERTEX, not from the midpoint.
- Forgetting the triangle inequality, so an impossible triangle (e.g. sides 2, 3, 6) is accepted.
📈 CAT exam insight & PYQ analysis
🎴 Flashcards — instant recall
Tap a card to reveal the answer. Drill these until they are automatic.
📌 Quick revision
Chapter test
🏆 Vidaara CAT success checklist
You have truly mastered Triangles when you can tick every box below.
- Recall every formula in this chapter without looking them up
- Solve each topic’s practice set with at least 80% accuracy
- Use the chapter shortcuts to cut your solving time in half
- Spot and avoid every common trap listed above
- Score 80%+ on the timed chapter test
📋 Chapter mastery scorecard
Track where you stand. Aim for the target before moving to the next chapter.
| Skill checkpoint | Target |
|---|---|
| Concept theory & formulas understood | 100% |
| Topic practice sets attempted (4 topics) | 4/4 |
| Best topic-test score | — → 80%+ |
| Chapter test score | — → 80%+ |
| Flashcards drilled to instant recall | 12 cards |
Formula Reference Sheet
Sides, area & similarity
| Angle sum / exterior angle | A + B + C = 180°; exterior = sum of two remote interior angles |
|---|---|
| Triangle inequality | |b − c| < a < b + c |
| Basic area | Area = ½ × base × height |
| Heron’s formula | Area = √[s(s−a)(s−b)(s−c)], s = (a+b+c)/2 |
| Similar triangles (AA) | Area ratio = (corresponding side ratio)² |
| Basic Proportionality (Thales) | DE ∥ BC ⇒ AD/DB = AE/EC |
Right triangles & centres
| Pythagoras | hypotenuse² = leg₁² + leg₂² (a² + b² = c²) |
|---|---|
| Common triples | 3-4-5, 5-12-13, 8-15-17, 7-24-25 (and multiples) |
| Centroid divides median | 2 : 1 from the vertex |
| Circumradius | R = abc / (4 × Area) |
| Inradius | r = Area / s, so Area = r × s |
| Equilateral (side a) | Area = (√3/4)a²; R = a/√3; r = a/(2√3) |